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lang-bash
$*inside the quoted string. If you want to create multiple arguments forecho, use"$@"with no spaces around$@." $@ "is two arguments if there are two positional parameters (the same as" $1" "$2 "). You would recreate" $1 $2 "with" $* ", assuming the first character of$IFSis a space.kshis that? Bothpdkshandksh93produces two lines fromset -- "a b" "c d"; printf '"%s"\n' " $@ ". This user tagged their question with bash, and that shell behaves the same, as doesdash.