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I am attempting to find files and then grep expression for some string in the files, then only get back the full directory path the files are found in.

find `pwd` -iname '*.py' -type f -exec bash -c "grep -l 'nn'; sed 's[\/](.*)*[\/]/d' {}" \; 

However, the sed expression will have the terminal hang, rather than recursively print out the files and removing the file from the directory path.

I know I can achieve this with:

find `pwd` -iname 'nn*' -type d 

However, I wanted to know the correct grep+sed arguments for future cases.

I am attempting to find files and then grep expression for some string in the files, then only get back the full directory path the files are found in.

find `pwd` -iname '*.py' -type f -exec bash -c "grep -l 'nn'; sed 's[\/](.*)*[\/]/d' {}" \; 

However, the sed expression will have the terminal hang, rather than recursively print out the files and removing the file from the directory path.

I can partially achieve this with:

find `pwd` -iname 'nn*' -type d 

However, this expects the directory name to have nn and not for nn inside the file.

I am attempting to find files and then grep expression for some string in the files, then only get back the full directory path the files are found in.

find `pwd` -iname '*.py' -type f -exec bash -c "grep -l 'nn'; sed 's[\/](.*)*[\/]/d' {}" \; 

However, the sed expression will have the terminal hang, rather than recursively print out the files and removing the file from the directory path.

I am attempting to find files and then grep expression for some string in the files, then only get back the full directory path the files are found in.

find `pwd` -iname '*.py' -type f -exec bash -c "grep -l 'nn'; sed 's[\/](.*)*[\/]/d' {}" \; 

However, the sed expression will have the terminal hang, rather than recursively print out the files and removing the file from the directory path.

I know I can achieve this with:

find `pwd` -iname 'nn*' -type d 

However, I wanted to know the correct grep+sed arguments for future cases.