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As far as I understand, to make kernel execve a non-ELF file, the file must be a script started with a she-bang #!, but I have a script run successfully without it, why does this happen?

xtricman⚓ArchVirtual⏺️~🤐ls a.sh -l -r-xr-xr-x 1 xtricman users 23 9月 26 18:45 a.sh xtricman⚓ArchVirtual⏺️~🤐cat a.sh echo "FDHDSFHGFKJJHGO" xtricman⚓ArchVirtual⏺️~🤐./a.sh FDHDSFHGFKJJHGO

This a.sh script doesn't contain a she-bang, so how does it run?

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  • Your current shell interprets it. Commented Sep 27, 2018 at 1:31

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If the file does not start with a "shebang" line, most shells will attempt to execute the lines in the file themselves.

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  • Can I disable this behavior of bash? Commented Sep 27, 2018 at 2:07
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    The shell will only do this on files marked "executable". If you don't want to execute the file then remove the x flag (chmod a-x a.sh) Commented Sep 27, 2018 at 2:41

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