I'd like to get a list of all mp3 files with >320 bitrate. I'm not sure, how to apply the regular expression to the output of exiftool -AudioBitrate command.
find . -type f -name '*.mp3' -print0 | while IFS= read -r -d '' i; do BITRATE=echo $(exiftool -AudioBitrate "$i")| grep -q '#([0-9]+) kbps#'; if $BITRATE > 320 then echo $BITRATE "$i" fi done Here is a bash script that works. It is basically what you have with a few tweaks:
#!/bin/bash set -o pipefail find . -type f -name "*.mp3" -print0 | while IFS= read -r -d '' file; do BITRATE=$(exiftool -AudioBitrate "$file" | grep -Eo '[0-9]+ kbps' | sed 's/ kbps//') if [[ $? -eq 0 ]] && [[ $BITRATE -ge 320 ]]; then echo $BITRATE "$file" fi done In setting the $BITRATE variable I run exiftool through a pipe directly and use $(...) to capture the output. Then, in the conditional I check if the exiftool -> grep pipe was successful and the bitrate is sufficiently high using Bash's numeric comparison operators.
I've checked that it handles some random .mp3 files I have lying around, including ones with spaces in the name.
No need for all those tools...
exiftool -q -if '$AudioBitrate > 320' -p '$AudioBitrate $Directory/$Filename' -ext mp3 -r . exiftool searches recursively in the current directory, only files with mp3 extension, and prints the bitrate and filename if the condition $AudioBitrate > 320 is satisfied
Simple and lazy way:
#!/bin/bash bitrateMin=320 find . -iname '*.mp3' -print0 | while IFS= read -r -d '' file; do [[ $(exiftool -AudioBitrate "$file" | awk -v br="$bitrateMin" '$4 >= br{print $4}') ]] && printf '%s\n' "$file" done 