Message275007
If the `step` parameter for `itertools.count()` rounds to 1 (f.i., 1.1, 1.437643, 1.99999), then it fallsback to fast (integer) mode and increases the counter by 1. Here's an example: Python 3.6.0a4+ (default:ddc95a9bc2e0+, Sep 8 2016, 14:46:19) >>> import itertools >>> for i in itertools.count(1, step=1.5): ... print(i) ... if i > 10: ... break 1 2 3 4 5 6 7 8 9 10 11 | |
| Date | User | Action | Args | | 2016-09-08 12:48:32 | StyXman | set | recipients: + StyXman | | 2016-09-08 12:48:32 | StyXman | set | messageid: <1473338912.37.0.468562809295.issue28019@psf.upfronthosting.co.za> | | 2016-09-08 12:48:32 | StyXman | link | issue28019 messages | | 2016-09-08 12:48:32 | StyXman | create | | |