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I found the following position online where White's best course is to force a threefold repetition with the sequence Qg5-Kh8-Qf6-Kg8 because all other moves lose:

[Title ""] [FEN "q4rk1/5p1p/5Q2/8/8/6P1/p4P1P/6K1 w - - 0 1"] [startflipped ""] 1. Qg5 Kh8 2. Qf6 Kg8 

This example uses 11 pieces and 29 material points (i.e., Queen = 9, Rook = 5, Bishop = 3, Knight = 3, Pawn = 1). I'm wondering if a position can be found with fewer pieces and/or fewer material points.

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2 Answers 2

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4 pieces is the minimum, and is attained by this position though Black has the option of trading Q for N to a bare-king draw:

[Title "Draw by perpetual check or insufficient material"] [FEN "8/8/8/8/8/7q/4NK2/7k w - - 0 0"] 1. Ng3+ Kh2 2. Nf1+ Kh1 3. Ng3+ Kh2 4. Nf1+ Kh1 5. Ng3+ 

For material points, this 5-piece position has only 5 MP's, and the perpetual check is absolutely forced

[Title "Draw by perpetual check"] [FEN "8/8/8/8/8/7p/p3NK2/7k w - - 0 0"] 1. Ng3+ Kh2 2. Nf1+ Kh1 3. Ng3+ Kh2 4. Nf1+ Kh1 5. Ng3+ 
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    One can also make a 4-piece, 4-point position that leads to a position equivalent to the first diagram after promotion, e.g. Kg3,Nh7/Kg1,f2: 1 Ng5! f1Q 2 Nh3+ Kh1 3 Nf2+ = Commented Aug 12, 2024 at 0:18
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[FEN "8/8/8/8/8/7p/8/5K1k w - - 0 1"] 

In this position, white's best is 1.Kf2 to force threefold repetition with 1...Kh2 2.Kf1 Kh1 etc.

Of course black can deviate, but that's also a draw (1...h2 2.Kf1 stalemate, or 2...Kg3 3.Kg1 h2+ 4.Kh1 Kh3 stalemate).

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