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  • \$\begingroup\$ Very nice. You can save some bytes by converting the array to a hexadecimal string, and using +('0x'+whatever) to convert it to a number: (_,c)=>b[(c/15|0)*14+ +('0x'+'0169abc7543268d'[c%15])] \$\endgroup\$ Commented Jan 20, 2017 at 12:45
  • \$\begingroup\$ Clever trick. I was already thinking of other ways to write the array, but I couldn't come up with any. I can still shorten that, by placing the hexadecimal number first and then the multiplication, making the space needless. \$\endgroup\$ Commented Jan 20, 2017 at 14:22
  • \$\begingroup\$ You could even do '0x'+'...'[c%15]-0+(c/15|0)*14 to save yourself a pair of parentheses :-) \$\endgroup\$ Commented Jan 20, 2017 at 14:32
  • \$\begingroup\$ You're right. Added. \$\endgroup\$ Commented Jan 20, 2017 at 14:40