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Feb 21, 2017 at 14:59 comment added user62131 Ah right. That doesn't affect Turing-completeness, of course (because an infinite loop that doesn't change the internal state can't contribute to a program's computational class).
Feb 21, 2017 at 13:23 comment added Martin Ender "Thue programs continue running until no more substitutions are possible, and this causes the Retina to work the same way" with the only exception that Retina will terminate early if one pass through the entire program fails to change the string. So you even get some simple infinite-loop detection for free.
Feb 21, 2017 at 4:58 history answered user62131 CC BY-SA 3.0