Timeline for Cops: Make a regex - Make a snake
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 13, 2017 at 12:39 | history | edited | CommunityBot | replaced http://codegolf.stackexchange.com/ with https://codegolf.stackexchange.com/ | |
| Mar 11, 2017 at 23:12 | history | edited | DLosc | CC BY-SA 3.0 | Added cracked notice |
| Mar 11, 2017 at 16:51 | comment | added | kennytm | Cracked codegolf.stackexchange.com/a/112653/32353 | |
| Mar 11, 2017 at 16:44 | comment | added | CalculatorFeline | Okay. Replace \W with .. Therefore, (\w+.)+ is equivalent to (\w*|\w.)+ is (\w+||\w.)+ is (\w+|\w.)+ is (\w|\w.)+ is (\w.?)+ and it's the same length but more efficient (one + vs two) | |
| Mar 10, 2017 at 22:36 | history | edited | DLosc | CC BY-SA 3.0 | Removed ^$ from regex because OP specified full match in question |
| Mar 10, 2017 at 21:25 | comment | added | mbomb007 | @CalculatorFeline There is nothing saying that the . can't be a word character. It could be a lowercase letter, or a digit. In fact, it could even be a capital letter, in the event that the last character of the program is one. | |
| Mar 10, 2017 at 19:27 | comment | added | CalculatorFeline | Well, my requirement is equivalent because \w+\W can be split into \w* and \w\W. (\w* is either null (trivial) or \w+ (easily snuck in with a symbol)) | |
| Mar 10, 2017 at 19:21 | comment | added | mbomb007 | @CalculatorFeline One or more letters. | |
| Mar 9, 2017 at 15:31 | comment | added | CalculatorFeline | So all symbols in the source must be preceded by a letter. | |
| Mar 9, 2017 at 3:38 | history | answered | DLosc | CC BY-SA 3.0 |