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\$\begingroup\$ Why using string parameters for Chr()? Seems to work fine without: ?Chr(&0124);Chr(&0150);Chr(&0145);…. \$\endgroup\$

manatwork
– manatwork

2013-04-17 14:24:58 +00:00
Commented Apr 17, 2013 at 14:24
1

\$\begingroup\$ Following your method, you could do it in 8 distinct characters: ?chr(1+), it will be something like ?chr(11+11+11+11+11+11+11+1+1+1+1+1+1+1)+chr(11+11+11+11+11+11+11+11+11+1+1+1+1+1)+ .... etc. \$\endgroup\$

AutomatedChaos
– AutomatedChaos

2013-04-19 06:22:19 +00:00
Commented Apr 19, 2013 at 6:22
\$\begingroup\$ Tested some more in VBA 7.1 (the one that comes with Office 2013) and there is no need for the semicolons either: ?Chr(&0124)Chr(&0150)Chr(&0145)…. \$\endgroup\$

manatwork
– manatwork

2013-04-20 08:20:16 +00:00
Commented Apr 20, 2013 at 8:20

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