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    \$\begingroup\$ Can be stripped down to: f=lambda x:x%1>0and(-x+x%1)or x+.1 which is only 34 characters long. \$\endgroup\$ Commented Jul 1, 2013 at 21:04
  • \$\begingroup\$ f=lambda x:[x+.1,x%1-x](x%1>0) is only 30 \$\endgroup\$ Commented Jul 1, 2013 at 23:15
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    \$\begingroup\$ One char shorter: f=lambda x:[x+.5,.5-x][x%1>0]. Note the use of .5 instead of .1 to get around precision issues \$\endgroup\$ Commented Jul 3, 2013 at 9:29
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    \$\begingroup\$ @AJMansfield 1.48 is not an integer. \$\endgroup\$ Commented Jul 12, 2013 at 15:48
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    \$\begingroup\$ No, that doesn't mean it. If he ment that, he should have written "all rational numbers". f:Q->Q does only mean that f maps rational number to rational numbers. Which my definition of f does. \$\endgroup\$ Commented Jul 12, 2013 at 16:01