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\$\begingroup\$ For interest's sake, there are 12 similar solutions (including this one) by swapping the non-vectorizing equals for the vectorizing equals, changing left-argument to first-argument or to identity, and swapping equals with not-equals and filter-in for filter-out for both vectorizing and non-vectorizing. :O \$\endgroup\$

hyperneutrino
– hyperneutrino ♦

2017-05-22 05:34:36 +00:00
Commented May 22, 2017 at 5:34
\$\begingroup\$ Let's say I posted the one that makes most sense, but with speed optimization. \$\endgroup\$

Erik the Outgolfer
– Erik the Outgolfer

2017-05-22 10:30:21 +00:00
Commented May 22, 2017 at 10:30

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