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edited Aug 14, 2017 at 17:47

Java 8, 74 bytes

Essentially just a port of Kamil'sKamil's second C# solution here.

n->{int g[][]=new int[n][n],i=0;for(;i<n*n;i+=n-1)g[i/n][i%n]=1;return g;}

Essentially just a port of Kamil's second C# solution here.

n->{int g[][]=new int[n][n],i=0;for(;i<n*n;i+=n-1)g[i/n][i%n]=1;return g;}

Essentially just a port of Kamil's second C# solution here.

n->{int g[][]=new int[n][n],i=0;for(;i<n*n;i+=n-1)g[i/n][i%n]=1;return g;}

answered Aug 12, 2017 at 3:45

Essentially just a port of Kamil's second C# solution here.

n->{int g[][]=new int[n][n],i=0;for(;i<n*n;i+=n-1)g[i/n][i%n]=1;return g;}