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\$\begingroup\$ Why are you fiddling around with padEnd and match? Can't you just slice each string to the correct length and then subtract them? \$\endgroup\$

Neil
– Neil

2017-09-18 09:14:00 +00:00
Commented Sep 18, 2017 at 9:14
\$\begingroup\$ @Neil Sorry I hadn't catch your point. The added padEnd is used for testcase f(0.001,2) and f(0.3,2). \$\endgroup\$

tsh
– tsh

2017-09-18 09:23:39 +00:00
Commented Sep 18, 2017 at 9:23
\$\begingroup\$ I was thinking you could simplify down to something along the lines of (r,p)=>{for(a=0,b=1;`${a/b}`.slice(0,p+2)-`${r}`.slice(0,p+2);a/b<r?a++:b++);return[a,b]} (not fully golfed). \$\endgroup\$

Neil
– Neil

2017-09-18 09:27:49 +00:00
Commented Sep 18, 2017 at 9:27
\$\begingroup\$ @Neil 120 -> 70 bytes. :) \$\endgroup\$

tsh
– tsh

2017-09-18 09:56:48 +00:00
Commented Sep 18, 2017 at 9:56
\$\begingroup\$ Whoa, that's much better! \$\endgroup\$

Neil
– Neil

2017-09-18 09:58:05 +00:00
Commented Sep 18, 2017 at 9:58

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