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Commonmark migration

edited Jun 17, 2020 at 9:04

#Axiom, 61 bytes

Axiom, 61 bytes

f n==(a:=factors n;reduce(max,[a.i.exponent for i in 1..#a]))

This is the first time i find it is possible define the function without the use of () parenthesis. Instead of "f(n)==" "f n==" one character less...

#Axiom, 61 bytes

f n==(a:=factors n;reduce(max,[a.i.exponent for i in 1..#a]))

This is the first time i find it is possible define the function without the use of () parenthesis. Instead of "f(n)==" "f n==" one character less...

f n==(a:=factors n;reduce(max,[a.i.exponent for i in 1..#a]))

This is the first time i find it is possible define the function without the use of () parenthesis. Instead of "f(n)==" "f n==" one character less...

answered Oct 21, 2017 at 21:35

user58988

#Axiom, 61 bytes

f n==(a:=factors n;reduce(max,[a.i.exponent for i in 1..#a]))

This is the first time i find it is possible define the function without the use of () parenthesis. Instead of "f(n)==" "f n==" one character less...