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Code Golf

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  • \$\begingroup\$ Save a byte with m* x*2 vUx. This makes me wonder if m* x*2 can be reduced further... \$\endgroup\$ Commented Dec 21, 2017 at 18:05
  • \$\begingroup\$ Thanks, @ETHproductions; that's another new trick I've learned today. \$\endgroup\$ Commented Dec 21, 2017 at 18:11
  • \$\begingroup\$ I've got it, just use x* and check if it's divisible by Ux*½ :) \$\endgroup\$ Commented Dec 21, 2017 at 18:11
  • \$\begingroup\$ Yes, I don't think that trick is documented anywhere... But whenever you use a binary operator as an auto-function with no second argument, it uses the index by default (like if you did XY{X*Y}) \$\endgroup\$ Commented Dec 21, 2017 at 18:12
  • \$\begingroup\$ Oh, now, that's just ingenious, @ETHproductions. :) \$\endgroup\$ Commented Dec 21, 2017 at 18:17