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\$\begingroup\$ You are using variable p in a single place, so no need for it. You can move the initialization of variable a into the for to spare its separate ;: for((a=$1;a>0;a/=10));do s=$[s+(a%10)**${#1}];done;echo $[s==$1]. \$\endgroup\$

manatwork
– manatwork

2013-11-15 11:08:23 +00:00
Commented Nov 15, 2013 at 11:08
1

\$\begingroup\$ By moving the evaluation into the for one more character can be shortened: for((a=$1;a>0;s+=(a%10)**${#1},a/=10));do :; done;echo $[s==$1]. \$\endgroup\$

manatwork
– manatwork

2013-11-15 11:16:45 +00:00
Commented Nov 15, 2013 at 11:16
\$\begingroup\$ Oh, curious! I tried something like that, but it didn't work. Curious what went wrong. \$\endgroup\$

user unknown
– user unknown

2013-11-16 01:53:57 +00:00
Commented Nov 16, 2013 at 1:53

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