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    \$\begingroup\$ Not completely sure... does this work too 1+(scan()-1)%/%100 (18 bytes) or I'm missing something ? \$\endgroup\$ Commented Jul 23, 2018 at 19:06
  • \$\begingroup\$ @digEmAll Nice! Seems to work fine. \$\endgroup\$ Commented Jul 23, 2018 at 21:16
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    \$\begingroup\$ the challenge doesn't say how far in the future we need to go but 1+scan()%/%99.99 may save 2 bytes (it will start to go wonky after 100 centuries) \$\endgroup\$ Commented Jul 25, 2018 at 12:26