Revisions to Check whether an integer is a power of 2 without using +,- operations [closed]

added 62 characters in body

edited Jan 5, 2014 at 8:35

python 3, 38

print(1==bin(int(input())).count('1'))

python, 32

However, the code doesn't work in every version.

print 1==bin(input()).count('1')

Notice that the solution works also for 0 (print False).

python 3, 38

print(1==bin(int(input())).count('1'))

python, 32

However, the code doesn't work in every version.

print 1==bin(input()).count('1')

python 3, 38

print(1==bin(int(input())).count('1'))

python, 32

However, the code doesn't work in every version.

print 1==bin(input()).count('1')

Notice that the solution works also for 0 (print False).

deleted 1 characters in body

edited Jan 4, 2014 at 19:05

python 3, 38

print(1==bin(int(input())).count('1'))

python, 33 32

However, the code doesn't work in every version.

print( 1==bin(input()).count('1'))

python 3, 38

print(1==bin(int(input())).count('1'))

python, 33

However, the code doesn't work in every version.

print(1==bin(input()).count('1'))

python 3, 38

print(1==bin(int(input())).count('1'))

python, 32

However, the code doesn't work in every version.

print 1==bin(input()).count('1')

answered Jan 4, 2014 at 18:07

python 3, 38

print(1==bin(int(input())).count('1'))

python, 33

However, the code doesn't work in every version.

print(1==bin(input()).count('1'))

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