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def f(s,i=1):n=s[:i-1]+s[i:];return(n==n[::-1])*i-i//len(i>len(s))or f(s,i+1)
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Returns the 1-indexed character if the operation can be done and -1 otherwise.
-1
def f(s,i=1):n=s[:i-1]+s[i:];return(n==n[::-1])*i-i//len(s)or f(s,i+1)
Try it online!
def f(s,i=1):n=s[:i-1]+s[i:];return(n==n[::-1])*i-(i>len(s))or f(s,i+1)
f=lambdadef f(s,i=1):i*(s[n=s[:i-1]==s[1]+s[i:i-len];return(s)%2n==n[::-1])*i-i//len(s)or f(s,i+1)
f=lambda s,i=1:i*(s[:i-1]==s[:i-len(s)%2:-1])-i//len(s)or f(s,i+1)
f=lambda s,i=1:i*(s[:i-1]==s[:i-len(s)%2:-1])-(i>leni//len(s))or f(s,i+1)
f=lambda s,i=1:i*(s[:i-1]==s[:i-len(s)%2:-1])-(i>len(s))or f(s,i+1)
