YaBASIC, score:15

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YaBASIC, score:15 Cracked by Dingus

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Can you crack it? Yes they can!

My method relies on 1 variable,i, which defaults to 0. !i (NOT i) results in 1. Of course, with 0 and 1 we've got binary - the building block of all computing. However, in my case I just added as many !i as needed to get the result. Pretty ugly...

?i ?!i ?(!i)+(!i) ?(!i)+(!i)+(!i) ?(!i)+(!i)+(!i)+(!i) ?(!i)+(!i)+(!i)+(!i)+(!i) ?(!i)+(!i)+(!i)+(!i)+(!i)+(!i) ?(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i) ?(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i) ?(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i) ?chr$((!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)+(!i)) 

And so on with ?chr$ and as many !i as needed for the desired character. In hindsight maybe adding = to the string would have slowed Dingus down by a few more minutes... Their solution uses it whereas mine doesn't. 😁

YaBASIC, score:15

The new and improved string to crack:

0 1 2 3 4 5 6 7 8 9 A I a i - 

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YaBASIC, score:15

The new and improved string to crack:

0 1 2 3 4 5 6 7 8 9 L S l s - 

Can you crack it?

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