Python 3.8, 91 bytes
import math f=lambda n,m,N=0,D=1:n and f(n-1,m,N*n**m+D,D*n**m)or(N/(G:=math.gcd(N,D)),D/G) Inputs \$n\$ and \$m\$ and returns the numerator and denominator of \$H_{n,m}\$ as a tuple.
Uses the formula from Arnauld's JavaScript answer.