Timeline for Vertices of a regular dodecahedron
Current License: CC BY-SA 4.0
15 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 23, 2023 at 7:18 | history | edited | Arnauld | CC BY-SA 4.0 | minor update |
| Jun 22, 2023 at 13:32 | history | edited | Arnauld | CC BY-SA 4.0 | added a commented version |
| Jun 22, 2023 at 13:11 | history | edited | Arnauld | CC BY-SA 4.0 | saved 2 bytes |
| Jun 22, 2023 at 13:03 | history | edited | Arnauld | CC BY-SA 4.0 | saved 5 bytes |
| Jun 22, 2023 at 12:57 | history | edited | Arnauld | CC BY-SA 4.0 | added a shorter version |
| Jun 21, 2023 at 18:18 | history | edited | Arnauld | CC BY-SA 4.0 | saved 3 bytes |
| Jun 21, 2023 at 18:09 | comment | added | xnor | I think you don't need to divide by 55 because the challenge allows the dodecahedron to be scaled. | |
| Jun 21, 2023 at 13:30 | history | edited | Arnauld | CC BY-SA 4.0 | saved 1 byte |
| Jun 21, 2023 at 12:06 | history | edited | Arnauld | CC BY-SA 4.0 | saved 2 bytes |
| Jun 21, 2023 at 10:19 | history | edited | Arnauld | CC BY-SA 4.0 | minor clarification |
| Jun 21, 2023 at 9:00 | history | edited | Arnauld | CC BY-SA 4.0 | saved 1 byte |
| Jun 21, 2023 at 8:46 | history | edited | Arnauld | CC BY-SA 4.0 | saved 5 bytes and added an explanation |
| Jun 21, 2023 at 8:37 | comment | added | alephalpha | You can use 89/55 as an approximation of the golden ratio. | |
| Jun 21, 2023 at 7:48 | history | edited | Arnauld | CC BY-SA 4.0 | saved 5 bytes |
| Jun 21, 2023 at 7:40 | history | answered | Arnauld | CC BY-SA 4.0 |