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  • \$\begingroup\$ It feels like there should be a way to omit the ,0 arg to printf and just have it print whatever garbage was left. Or just spaces? But printf("%*c",i) prints a byte of garbage at the end, and we probably can't consider that a "terminator". Perhaps for(;i--;)puts(""); to use newline as the unary character? \$\endgroup\$ Commented Aug 14, 2023 at 22:44
  • \$\begingroup\$ Or if you want to write a function that returns a string instead of printing, perhaps memset(s,7,i);s[i]=0; to replace the input string with that many ASCII "BEL" characters and a terminator, but that might not be shorter. Or memset(...); return i; for an explicit-length string. (And relies on the caller to allocate a large enough buffer without having parsed the string of binary digits, so only a larger fixed-size buffer could work.) \$\endgroup\$ Commented Aug 14, 2023 at 22:47
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    \$\begingroup\$ @PeterCordes Good ideas, but I only managed to get the first one to work (leaving off ,0). Thanks anyways! \$\endgroup\$ Commented Aug 16, 2023 at 18:11
  • \$\begingroup\$ Doesn't seem to work anymore; 58 byte with spaces as digits \$\endgroup\$ Commented May 6, 2024 at 14:51
  • \$\begingroup\$ 55 bytes with Peter's suggestion of newline as unary char \$\endgroup\$ Commented May 6, 2024 at 14:56