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Rev

\$\begingroup\$ Nice algebraic approach! There's a minor bug though: 10/@3%= tries to access the fourth element of an array of length 3 if the input is 35. \$\endgroup\$

Dennis
– Dennis

2014-04-30 05:35:49 +00:00
Commented Apr 30, 2014 at 5:35
\$\begingroup\$ @Dennis, yes, I realised after I went to bed. I can think of various ways of fixing it, all costing 2. \$\endgroup\$

Peter Taylor
– Peter Taylor

2014-04-30 07:32:02 +00:00
Commented Apr 30, 2014 at 7:32
\$\begingroup\$ You can get one char back with 9/3%@3%=. \$\endgroup\$

Dennis
– Dennis

2014-04-30 16:44:55 +00:00
Commented Apr 30, 2014 at 16:44
\$\begingroup\$ I'm currently 7 chars up with some more drastic restructuring. But that 1 char of 9/ instead of 10/ still works, so thanks. \$\endgroup\$

Peter Taylor
– Peter Taylor

2014-04-30 16:46:35 +00:00
Commented Apr 30, 2014 at 16:46

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