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edited Nov 1, 2023 at 20:33

C (gcc), 9998 bytes

-1 thanks to ceilingcat

Adapted from my JS answer. Prints the bounds separated by a space.

m,M,x,p;f(n){for(M=n*n,m=1,x=p=2;m=(x*=p)>n|x<m?m:x,x<n?1:x<M?M=x:(x=++p)<n;);printf("%d %d",m,M);}

Adapted from my JS answer. Prints the bounds separated by a space.

m,M,x,p;f(n){for(M=n*n,m=1,x=p=2;m=(x*=p)>n|x<m?m:x,x<n?1:x<M?M=x:(x=++p)<n;);printf("%d %d",m,M);}

-1 thanks to ceilingcat

Adapted from my JS answer. Prints the bounds separated by a space.

m,M,x,p;f(n){for(M=n*n,m=1,x=p=2;m=(x*=p)>n|x<m?m:x,x<n?:x<M?M=x:(x=++p)<n;);printf("%d %d",m,M);}

answered Nov 1, 2023 at 14:14

Adapted from my JS answer. Prints the bounds separated by a space.

m,M,x,p;f(n){for(M=n*n,m=1,x=p=2;m=(x*=p)>n|x<m?m:x,x<n?1:x<M?M=x:(x=++p)<n;);printf("%d %d",m,M);}