Python 3, Sp3000

x=n= int(input()) # 3 P = [1,1] #+2 = 5 k = 2 while n >=len(P): #+1 = 6 k += 1 for x in P: if k%x ==~0: break #+1 = 7 else: P += [P[-2]+x] #+7 = 14 print(x)

#Python 3, Sp3000

x=n= int(input()) # 3 P = [1,1] #+2 = 5 k = 2 while n >=len(P): #+1 = 6 k += 1 for x in P: if k%x ==~0: break #+1 = 7 else: P += [P[-2]+x] #+7 = 14 print(x)

Python 3, Sp3000

x=n= int(input()) # 3 P = [1,1] #+2 = 5 k = 2 while n >=len(P): #+1 = 6 k += 1 for x in P: if k%x ==~0: break #+1 = 7 else: P += [P[-2]+x] #+7 = 14 print(x)

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edited Apr 13, 2017 at 12:39

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#Python 3, Sp3000 Python 3, Sp3000

x=n= int(input()) # 3 P = [1,1] #+2 = 5 k = 2 while n >=len(P): #+1 = 6 k += 1 for x in P: if k%x ==~0: break #+1 = 7 else: P += [P[-2]+x] #+7 = 14 print(x)

#Python 3, Sp3000

x=n= int(input()) # 3 P = [1,1] #+2 = 5 k = 2 while n >=len(P): #+1 = 6 k += 1 for x in P: if k%x ==~0: break #+1 = 7 else: P += [P[-2]+x] #+7 = 14 print(x)

#Python 3, Sp3000

x=n= int(input()) # 3 P = [1,1] #+2 = 5 k = 2 while n >=len(P): #+1 = 6 k += 1 for x in P: if k%x ==~0: break #+1 = 7 else: P += [P[-2]+x] #+7 = 14 print(x)

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edited Dec 29, 2014 at 6:37

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#Python 3, Sp3000

x=n= int(input()) # 3 P = [1,2]1] #+2 = 5 k = 2 while n >=len(P): #+1 = 6 k += 1 for x in P: if k%x ==~0: break #+1 = 7 else: P += [P[-2]+x] #+7 = 14 print(x)

#Python 3, Sp3000

x=n= int(input()) # 3 P = [1,2] #+2 = 5 k = 2 while n >=len(P): #+1 = 6 k += 1 for x in P: if k%x ==~0: break #+1 = 7 else: P += [P[-2]+x] #+7 = 14 print(x)

#Python 3, Sp3000

x=n= int(input()) # 3 P = [1,1] #+2 = 5 k = 2 while n >=len(P): #+1 = 6 k += 1 for x in P: if k%x ==~0: break #+1 = 7 else: P += [P[-2]+x] #+7 = 14 print(x)

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answered Dec 29, 2014 at 6:26

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Python 3, Sp3000

Python 3, Sp3000