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  • 6
    \$\begingroup\$ N0 l33t? “t0 b3” \$\endgroup\$ Commented Feb 10, 2016 at 20:18
  • 7
    \$\begingroup\$ Why does it have to be a function? \$\endgroup\$ Commented Feb 10, 2016 at 20:19
  • 2
    \$\begingroup\$ @rybo111 Well! That seems like they didn't understand the concept then ;) \$\endgroup\$ Commented Feb 10, 2016 at 20:19
  • 14
    \$\begingroup\$ This one begs for a Shakespeare solution. Non-competing of course, as the byte count would undoubtedly be huge... \$\endgroup\$ Commented Feb 10, 2016 at 22:15
  • 1
    \$\begingroup\$ @LuisMendo OK. Either is fine. Supporting both is not necessary. \$\endgroup\$ Commented Feb 10, 2016 at 22:26