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Commonmark migration
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##Pyke, 35 bytes

Pyke, 35 bytes

35F\";"\\+3322 5**F;H)s"\"2*+2* H)s 

Try it here!

To check: remove the final H and the resulting string contains the right number of each character (with the extra H)

This does NOT use a generalised quine or in fact a quine at all. It relies on being able to create a string containing all the characters in the source. It should be able to do it for any code but each character logarithmically increases code size. The only number of times a character is allowed in the source is 2 or 7

##Pyke, 35 bytes

35F\";"\\+3322 5**F;H)s"\"2*+2* H)s 

Try it here!

To check: remove the final H and the resulting string contains the right number of each character (with the extra H)

This does NOT use a generalised quine or in fact a quine at all. It relies on being able to create a string containing all the characters in the source. It should be able to do it for any code but each character logarithmically increases code size. The only number of times a character is allowed in the source is 2 or 7

Pyke, 35 bytes

35F\";"\\+3322 5**F;H)s"\"2*+2* H)s 

Try it here!

To check: remove the final H and the resulting string contains the right number of each character (with the extra H)

This does NOT use a generalised quine or in fact a quine at all. It relies on being able to create a string containing all the characters in the source. It should be able to do it for any code but each character logarithmically increases code size. The only number of times a character is allowed in the source is 2 or 7

added 23 characters in body
Source Link
Blue
  • 28.8k
  • 8
  • 53
  • 101

##Pyke, 2735 bytes

77;7\\D7\DD7\7D7\sD\HD\;DsH35F\";"\\+3322 5**F;H)s"\"2*+2* H)s 

Try it here!Try it here!

To check: remove the final H and the resulting string contains the right number of each character (with the extra H)

This does NOT use a generalised quine or in fact a quine at all. It relies on being able to create a string containing all the characters in the source. It should be able to do it for any code but each character logarithmically increases code size. The only number of times a character is allowed in the source is 2 or 7

##Pyke, 27 bytes

77;7\\D7\DD7\7D7\sD\HD\;DsH 

Try it here!

To check: remove the final H and the resulting string contains the right number of each character (with the extra H)

This does NOT use a generalised quine or in fact a quine at all. It relies on being able to create a string containing all the characters in the source. It should be able to do it for any code but each character logarithmically increases code size. The only number of times a character is allowed in the source is 2 or 7

##Pyke, 35 bytes

35F\";"\\+3322 5**F;H)s"\"2*+2* H)s 

Try it here!

To check: remove the final H and the resulting string contains the right number of each character (with the extra H)

This does NOT use a generalised quine or in fact a quine at all. It relies on being able to create a string containing all the characters in the source. It should be able to do it for any code but each character logarithmically increases code size. The only number of times a character is allowed in the source is 2 or 7

Source Link
Blue
  • 28.8k
  • 8
  • 53
  • 101

##Pyke, 27 bytes

77;7\\D7\DD7\7D7\sD\HD\;DsH 

Try it here!

To check: remove the final H and the resulting string contains the right number of each character (with the extra H)

This does NOT use a generalised quine or in fact a quine at all. It relies on being able to create a string containing all the characters in the source. It should be able to do it for any code but each character logarithmically increases code size. The only number of times a character is allowed in the source is 2 or 7