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\$\begingroup\$ I think (like my CJam) answer, it's not necessary to use a standard quine as the basis. A direct port of my CJam solution gives 64 bytes: 64.times{$><<"64.times{$><<.inspect[rand 32]}".inspect[rand 32]} \$\endgroup\$

Martin Ender
– Martin Ender

2016-09-09 08:44:08 +00:00
Commented Sep 9, 2016 at 8:44
\$\begingroup\$ Nevermind, basing it on a standard quine is shorter, but you'll have to use the eval-based quine: eval r="47.times{$><<('eval r=%p'%r)[rand 47]}" \$\endgroup\$

Martin Ender
– Martin Ender

2016-09-09 08:53:35 +00:00
Commented Sep 9, 2016 at 8:53
\$\begingroup\$ @MartinEnder That's different enough to merit its own answer, I think. If you disagree, feel free to edit it into mine, but in the mean time I'll just steal a few tricks from yours to save a few bytes in mine. \$\endgroup\$

anon
– anon

2016-09-09 14:05:33 +00:00
Commented Sep 9, 2016 at 14:05

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