Specifically, this references JavaScript, a programming language that happens to be one you can run on StackExchange/StackOverflow. However, you may use any programming language to do this challenge. This is not actual JS golfing, but merely a "code-golfable" challenge. Actual complete parsing of JS is not needed.
An example of JS looks like this (try running all the snippets in here):
const constant = 1 var value = 2 for (let i = 0; i < 21; i++) { value += constant + value // Addition } // Print the value document.write(value)Problem is, I want my code size to be a bit smaller. So, I could rename the variables to make it look like this:
var a = 1 var b = 2 for (let i = 0; i < 21; i++) { b += a + b // Addition } // Print the value document.write(b)Notice how the variables have been changed to one letter, and the const keyword has been shortened to var. Then, we can remove most spaces and all comments:
var a=1 var b=2 for (let i = 0; i < 21; i++) { b+=a+b } document.write(b)So, here are the rules (look at the test case; it will make more sense):
- The keywords
const,let,var,while, andforare not variables (notice the spaces!) and should not be changed, with the exception ofconst, which should be changed tovarfor shortening. - A variable is defined as the longest string of characters that contain only the characters
0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ_$, not including the rule above. Furthermore, a variable is a variable if and only if one variable is preceded withconst,let, orvar(with spaces). - All variables with the same name must be renamed into a single character variable (one of
abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ_$). All variables with different names must have different values in the result. You may assume that there are no more than 50 unique variables, so only one character is required. - A single-line comment is all the characters at or after
// - All single-line comments should be removed.
- All spaces that are not within keywords must be removed. (Not newlines!)
- After all of this, remove any empty lines. This includes comment removal.
- Compact numbers! If a number is an integer, it is defined a number, but with a
.and all zeros at the end. - If an integer has more than two zeros, write the number before the final zeros (before the dot), an
e, then the number of zeros (30000to3e4,1515000to1515e3). This is optional for two zeros. While this is not complete, it would be too complicated to compact numbers well. - You should output all other characters normally.
There is only one test case, but it is a strange one!
Test case:
// Hello world, but stranger! // funny spacing const m = 72000.00 / 1000 var h = String.fromCharCode(m) let string = " world!" // Value to print var l for (let i = 1.00000; i < string.length; i++) { // Number prototype to throw off some lazy variable detection Number console.log(string[i]) // Print each value l += string[i] } string = string.split("").join("<br>") h = l.toUpperCase() document.write("<!DOCTYPE html><i>" + h.toUpperCase() + " " + string + "</i>")Result:
var m=72e3/1e3 var h=String.fromCharCode(m) let s=" world!" var l for(let i=1;i<s.length;i++){ Number console.log(s[i]) l+=s[i] } s=s.split("").join("<br>") h=l.toUpperCase() document.write("<!DOCTYPE html><i>"+h.toUpperCase()+" "+s+"</i>")Notice Number! This is code-golf, so the shortest answer in bytes wins.
0123456789? And would it be a valid assumption that all long variable names don't start with a digit? \$\endgroup\$constchange tovaror not? (first rule says no, first example says yes) \$\endgroup\$for (let i = 0; i < 21; i++) {in the final iteration of the examplefor(let i=0;i<21;i++){(spaces removed, except afterlet)? \$\endgroup\$