Given two integers as input in an array, draw a rectangle, using the first integer as width and second as height.
Or, if your language supports it, the two integers can be given as separate inputs.
Assume the width and height will never be less than 3, and they will always be given.
Example Outputs:
[3, 3]
|-| | | |-| [5, 8]
|---| | | | | | | | | | | | | |---| [10, 3]
|--------| | | |--------| This is code-golf, so the answer with the lowest amount of bytes wins.
p="|" def r(w,h):m=w-2;b=p+"-"*m+p;return b+"\n"+(p+m*" "+p+"\n")*(h-2)+b 
let v = {(c:String,n:Int) -> String in var s = "";for _ in 1...n {s += c};return s;};_ = {var s = "|"+v("-",$0-2)+"|\n" + v("|"+v(" ",$0-2)+"|\n",$1-2) + "|"+v("-",$0-2)+"|";print(s);}(10,5) I think Swift 3 could golf this a lot more but I don't feel like downloading Swift 3.
let d x y= let q = String.replicate (x-2) [for r in [1..y] do printfn "%s%s%s" "|" (if r=y||r=1 then(q "-")else(q " ")) "|"] Saved 9 bytes thanks to milk - completely forgot to concatenate strings. The compare trick is pretty cool too.
w=>h=>{var s="";for(int i=0;i<h;)s+="|"+new String(1>i++%(h-1)?'-':' ',w-2)+"|\n";return s;}; Full source, including test cases:
using System; namespace DrawASCIIRectangle { class Program { static void Main(string[] args) { Func<int,Func<int,string>> d= w=>h=>{var s="";for(int i=0;i<h;)s+="|"+new String(1>i++%(h-1)?'-':' ',w-2)+"|\n";return s;}; Console.WriteLine(d(3)(3)); Console.WriteLine(d(5)(8)); Console.WriteLine(d(10)(3)); } } } 
1>i++%(h-1) instead of i++<1||i>h-1 will save 1 byte. You can also put all the string concats into a single statement so the for is a one liner and doesn't need braces, saving another 8 bytes: s+="|"+new string(1>i++%(h-1)?'-':' ',w-2)+"|\n" \$\endgroup\$ def r(w,h): print '\n'.join(['|'+('-' if i%(h-1)==0 else ' ')*(w-2)+'|' for i in range(h)]) Edit: lambda function for a few less bytes (thanks @DJMcMayhem)
r=lambda w,h:'\n'.join(['|'+('-'if i%(h-1)==0 else' ')*(w-2)+'|'for i in range(h)]) Edit#2: if notation is greedy
r=lambda w,h:'\n'.join(['|'+(0<i<h-1 and' 'or'-')*(w-2)+'|'for i in range(h)]) Edit#3: -8 bytes with list trick
r=lambda w,h:'\n'.join(['|'+'- '[0<i<h-1]*(w-2)+'|'for i in range(h)]) 
print (you can just return instead) \$\endgroup\$ C 87 bytes
f(b,a,c,k){for(;c<a*b;++c)printf("%s",(k=c%b)==b-1?"|":!k?"\n|":c<b||c>a*b-b?"-":" ");} this is the main for some test...
main() {f(3,3,0,0); f(5,8,0,0); f(10,3,0,0); return 0; } |-| | | |-| |---| | | | | | | | | | | | | |---| |--------| | | |--------| 
f=(w,h)=>{s=`|${"-".repeat(w-2)}|`;return s+` `+("|"+" ".repeat(w-2)+`| `).repeat(h-2)+s} 
f= as part of the byte count per consensus (unless it's recursive, because you need to define its name then), so your code is 87 bytes long. On top of that, this site allows using curried functions, so you can use w=>h=> instead of (w,h)=> (Only useful if you have two parameters). With this in mind, you can use other tricks in order to easily get 74 bytes. \$\endgroup\$ VJE.[Q*-Q2?}N,0tJ\-d\| A program that takes input of the width, followed by the height, on STDIN and prints the result.
How it works
VJE.[Q*-Q2?}N,0tJ\-d\| Program. Inputs: Q, E JE Assign E to J V For N in [0, 1, 2, ..., J-1]: ,0tJ Yield [0, J-1] }N N is in that list ? If that: \- Yield "-" Else: d Yield " " *-Q2 Repeat that Q-2 times .[Q \| Evenly pad that with "|" on both sides to length Q Implicitly print 
¬'|@α(¬;)' *╗`╜o'|o`Mi('-*"|%s|"%;) Explanation:
¬'|@α(¬;)' *╗`╜o'|o`Mi('-*"|%s|"%;) ¬ height - 2 '|@α ["|" for _ in range(height-2)] (¬;) width - 2, duplicate, move to bottom of stack ' * " "*(width-2) ╗ save to register 0 `╜o'|o`M for each "|" in list of "|"s: ╜o append (width-2) spaces '|o append a second "|" i flatten list ( bring copy of (width-2) back to top '-* "-"*(width-2) "|%s|"% surround with "|"s ;) dupe, move copy to bottom of stack (implicitly print stack contents, one element per line) (λ(w h)(for((j h))(display #\|)(for((i(- w 2)))(display(if(or(= j 0)(= j(- h 1)))#\-" ")))(displayln #\|))) Ungolfed:
(define f (λ (w h) (for ((j h)) (display #\|) (for ((i (- w 2))) (display (if (or (= j 0) (= j (- h 1))) #\- " "))) (displayln #\|)))) Testing:
(f 5 3) Output:
|---| | | |---| 
'|','|',⍨'-'⍪'-'⍪⍨''⍴⍨-∘2 -∘2 subtract two
''⍴⍨ use that as height and width to reshape an empty string (padding with spaces)
'-'⍪⍨ put dashes below
'-'⍪ put dashes on top
'|',⍨ put stiles on the right
'|', put stiles on the left
'|'(,,⊣)'-'(⍪⍪⊣)''⍴⍨-∘2 \$\endgroup\$ [a,b]=input().split() def d(e):print("|"+e*(int(a)-2)+"|") d("-") for f in range(2,int(b)):d(" ") d("-") puts [set M |[string repe - [incr w -2]]|] incr w time {puts |[format %$w\s |]} [incr h -2] puts $M 
def f(a,b): c='|'+'-'*(a-2)+'|\n';print(c+c.replace(*'- ')*(b-2)+c) 
{for(;i++<$2;)for(j=0;j++<$1;)printf 1~j?"|":$1~j?"|\n":1~i||$2~i?"-":FS} Just writes char by char, line by line. Couldn't seem to save space with fancy functions.
