Ruby, <strike>53</strike> <strike>55</strike> 52 bytes
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 f=->(a,b){/^(2|t[wo]?o|t0)$/i=~a&&/^b(e?e?|3)$/i=~b}

I'll be honest, this is my first attempt at trying to golf a problem.

Function call in the form of `f.call(firstValue, secondValue)`

`0` is Truthy, `nil` is Falsy.

Test it [Here][1]


 [1]: https://repl.it/BlrV/2