precedence

Can any one please explain the mechanics of this code, the answer for this question is False, why?
1: public class Q10
2: {
3: public static void main(String[] args)
4: {
5: int i = 10;
6: int j = 10;
7: boolean b = false;
8:
9: if( b = i == j)
10: System.out.println("True");
11: else
12: System.out.println("False");
13: }
14: }

I get "True"...dont know where the false is coming from.
Yo can break down the if like this:
if(b=(i==j))
Ok so you see that i==j which is 10==10
This is true no problem.
Next we have b=(i==j). We know that i==j is true, so we cna insert it in to the statement.
So we have b=true.
Note this is a assignment and not a test to see if thye are the same. so what we are doing is setting b to equal true. Hence it evaluates ot true and prints true.
Hope that helps.
Faisal

But I run in my machine. The answer is true.
And I think this is the right answer, too.
regds,
Calanthe

shankareb,
please read the JavaRanch Naming Policy and register again.
Thank you for your cooperation

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Valentin Crettaz
Sun Certified Programmer for Java 2 Platform