incrementation of variable

hi friends;
i have a doubt abt incrementation of variable.
see the following code:


In the above code the o/p is 1.
But by logical view the o/p should be 2 as shown in the commented code.
Why x is not getting incremented after line 3?

Bye......
shubha.

( tags added)
[ June 16, 2005: Message edited by: Barry Gaunt ]

Hi,

Because x = x++; is still the same.

Your saying x = x++; it's not being incremented x is just = x.

In x++ the ++ (postfix is being ignored) you need to use ++x; if you want to increment it.

Hope this made sense!

You may find that Corey's tip help to explain what's happening.

your commented code is different than the code you run - they are not equivilent.

here's why...

JUST before we get to line three, x is 1. we now start doing what line 3 says to do...

first, get x. that's 1. we'll remember that value for later, first i have to take care of that ++. So, now i increment x. x is 1, so i'll increment it to 2. now, lets take care of that assignment thing. the right hand side of my statement was... let's see, i remembered that... oh yeah!!! it's 1!!!.

so now, i'll assign 1 to x.

and so it prints 1.

Hi everyone;

i have still doubt,

if we run the code as;

class Test{
public static void main(String args[]) {
int y=0;
++y;
y++;
System.out.println(y);
}
}

gives me o/p as 2.In the 1st code I did the same operation.

Hi everyone;

i have still doubt,

if we run the code as;

class Test{
public static void main(String args[]) {
int y=0;
++y;
y++;
System.out.println(y);
}
}

gives me o/p as 2.In the 1st code I did the same operation.

x++;

and

x = x++;

Do NOT do the same thing.

The first one says "increment x."

The second one is a bit confusing. It says...

- grab the current value of x (let's assume it's 0)
- increment x (it's 1)
- assign the grabbed value to the variable on the left (x)
- so x gets 0 (the value we grabbed)

If you changed:

x = x++;

to:

x = ++x;

You'd get something more like what you expect because x gets incremented BEFORE the assignment takes place.

Of course, no one in their right mind would actually write either of these since just writing:

x++;

is MUCH more clear.

Hope that helps.
[ June 16, 2005: Message edited by: Dave Wood ]