confusion with primitives

why are the m and n values same??? though we have assigned a -m to n...

Try so see output of following code. You will get the reason.

sorry Himanshu,
i didn't understand what you were trying to tell

1.4E-45 -1.4E-45
-2147483648 -2147483648
-1 1
integer max value: 2147483647

Output completed (0 sec consumed)

i got the following output...

why is n being assigned a -ve value where we assigned -m to n

Hi, check compiling this code.



I think it will clear your doubt.
The Range of byte is -128 - 127.
So it cannot hold a value -b1 which is +128.

thanks himanshu and abhi

i understood now

The min value of any integer type is represented at the bit level by the fist bit (the sign bit) being one, and the rest of the bits being 0. This means that:

1000...00 // MIN_VALUE
0111...11 // MIN_VALUE 1's complement
1000...00 // MIN_VALUE 1's complement + 1 = MIN_VALUE 2's complement

So MIN_VALUE and -MIN_VALUE are always the same.

The same is obviously not the case of MAX_VALUE and -MAX_VALUE, since the bit patterns capable of representing negative integers is one more than those capable of representing strictly positive integers.

0111...11 // MAX VALUE
1000...00 // MAX VALUE 1's complement
1000...01 // MAX_VALUE 2's complement

In this case, negating MAX_VALUE will give you what you would expect from a mathematical point of view.