In Python 3 itertools gained a new function accumulate that does what you want. I'd recommend that you instead used this function. Or if you can't if you're in Python 2 to upgrade. This would single handedly change your code to:

from itertools import accumulate new_l = accumulate(l) 

If you however done this as a learning exercise, then I'd instead use iterators. I'd first change l to an iterator, via iter. Which would allow you to use next to remove the default value. After this I would then loop through the iterator and yield rather than new_list.append the new values. This can allow you to get something like:

def accumulate_sum(l): l = iter(l) try: total = next(l) except StopIteration: return yield total for item in l: total += item yield total 

Which funnily enough is almost exactly the same to how it's done in itertools.accumulate. If you wanted to at a later date use a different function rather than addition, then you could pass that as a function, to call on each iteration.

In Python 3 itertools gained a new function accumulate that does what you want. I'd recommend that you instead used this function. Or if you can't if you're in Python 2 to upgrade. This would single handedly change your code to:

from itertools import accumulate new_l = accumulate(l) 

If you however done this as a learning exercise, then I'd instead use iterators. I'd first change l to an iterator, via iter. Which would allow you to use next to remove the default value. After this I would then loop through the iterator and yield rather than new_list.append the new values. This can allow you to get something like:

def accumulate_sum(l): l = iter(l) try: total = next(l) except StopIteration: return yield total for item in l: total += item yield total 

Which funnily enough is almost exactly the same to how it's done in itertools.accumulate. If you wanted to at a later date use a different function rather than addition, then you could pass that as a function, to call on each iteration.

In Python 3 itertools gained a new function accumulate that does what you want. I'd recommend that you instead used this function. Or if you can't if you're in Python 2 to upgrade. This would single handedly change your code to:

from itertools import accumulate new_l = accumulate(l) 

In Python 3 itertools gained a new function accumulate that does what you want. I'd recommend that you instead used this function. Or if you can't if you're in Python 2 to upgrade. This would single handedly change your code to:

from itertools import accumulate new_l = accumulate(l) 

If you however done this as a learning exercise, then I'd instead use iterators. I'd first change l to an iterator, via iter. Which would allow you to use next to remove the default value. After this I would then loop through the iterator and yield rather than new_list.append the new values. This can allow you to get something like:

def accumulate_sum(l): l = iter(l) try: total = next(l) except StopIteration: return yield total for item in l: total += item yield total 

Which funnily enough is almost exactly the same to how it's done in itertools.accumulate. If you wanted to at a later date use a different function rather than addition, then you could pass that as a function, to call on each iteration.