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Your solution seems generally sound. I would make a few changes:

You are surrounding your whole code in a try-catch block. Instead, surround the area where the IOException has a chance of being thrown (Also, use System.err to print for errors):

try { BufferedReader in = new BufferedReader(new InputStreamReader( System.in)); } catch (IOException) { System.err.println("Error"); } 

And since the in is inside the try-catch and it is required outside, do:

BufferedReader in = null; try { in = new BufferedReader(new InputStreamReader( System.in)); } catch (IOException) { System.err.println("Error"); System.exit(1); } 

Your solution seems generally sound. I would make a few changes:

You are surrounding your whole code in a try-catch block. Instead, surround the area where the IOException has a chance of being thrown (Also, use System.err to print for errors):

try { BufferedReader in = new BufferedReader(new InputStreamReader( System.in)); } catch (IOException) { System.err.println("Error"); } 

And since the in is inside the try-catch and it is required outside, do:

BufferedReader in = null; try { in = new BufferedReader(new InputStreamReader( System.in)); } catch (IOException) { System.err.println("Error"); return; } 

Your solution seems generally sound. I would make a few changes:

You are surrounding your whole code in a try-catch block. Instead, surround the area where the IOException has a chance of being thrown (Also, use System.err to print for errors):

try { BufferedReader in = new BufferedReader(new InputStreamReader( System.in)); } catch (IOException) { System.err.println("Error"); } 

And since the in is inside the try-catch and it is required outside, do:

BufferedReader in = null; try { in = new BufferedReader(new InputStreamReader( System.in)); } catch (IOException) { System.err.println("Error"); return; } 

Your solution seems generally sound. I would make a few changes:

You are surrounding your whole code in a try-catch block. Instead, surround the area where the IOException has a chance of being thrown (Also, use System.err to print for errors):

try { BufferedReader in = new BufferedReader(new InputStreamReader( System.in)); } catch (IOException) { System.err.println("Error"); } 

And since the in is inside the try-catch and it is required outside, do:

BufferedReader in = null; try { in = new BufferedReader(new InputStreamReader( System.in)); } catch (IOException) { System.err.println("Error"); System.exit(1); } 

Your solution seems generally sound. I would make a few changes:

You are surrounding your whole code in a try-catch block. Instead, surround the area where the IOException has a chance of being thrown (Also, use System.err to print for errors):

try { BufferedReader in = new BufferedReader(new InputStreamReader( System.in)); } catch (IOException) { System.err.println("Error"); } 

Your solution seems generally sound. I would make a few changes:

You are surrounding your whole code in a try-catch block. Instead, surround the area where the IOException has a chance of being thrown (Also, use System.err to print for errors):

try { BufferedReader in = new BufferedReader(new InputStreamReader( System.in)); } catch (IOException) { System.err.println("Error"); } 

And since the in is inside the try-catch and it is required outside, do:

BufferedReader in = null; try { in = new BufferedReader(new InputStreamReader( System.in)); } catch (IOException) { System.err.println("Error"); return; }