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- $\begingroup$ I read once something about block ciphers being a pseudorandom permutations. This means that D(x,k) and E(x,k) are just operations on a "substitution table". $\endgroup$Filip Franik– Filip Franik2016-03-10 07:30:08 +00:00Commented Mar 10, 2016 at 7:30
- $\begingroup$ Yes, so... I can't find the logical difference between them... $\endgroup$Shu Suzuki– Shu Suzuki2016-03-10 07:31:20 +00:00Commented Mar 10, 2016 at 7:31
- $\begingroup$ Difference is strictly formal. The overall behavior is a "substitution". $\endgroup$Filip Franik– Filip Franik2016-03-10 07:35:28 +00:00Commented Mar 10, 2016 at 7:35
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