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Dec 3, 2018 at 6:43 history edited fgrieu CC BY-SA 4.0
Polish
Dec 3, 2018 at 6:41 comment added fgrieu @nachofest: I have polished the answer to explain that. I now also use $D$ for the distinguisher, which seems more common and avoids confusion between the distinguisher and its advantage.
Dec 3, 2018 at 6:35 history edited fgrieu CC BY-SA 4.0
Polish
Dec 2, 2018 at 21:30 comment added nachofest perfect! Only one doubt about it, why is $Pr[A(r)=1]=2^{−(n−1)} $ ?
Dec 2, 2018 at 19:43 history edited fgrieu CC BY-SA 4.0
Oups
Dec 2, 2018 at 12:38 history edited fgrieu CC BY-SA 4.0
Polish
Dec 2, 2018 at 12:24 history edited fgrieu CC BY-SA 4.0
Polish
Dec 2, 2018 at 12:18 history edited fgrieu CC BY-SA 4.0
Fix
Dec 2, 2018 at 12:13 history edited fgrieu CC BY-SA 4.0
Fix
Dec 2, 2018 at 12:07 history edited fgrieu CC BY-SA 4.0
Finish
Dec 2, 2018 at 11:38 vote accept nachofest
Dec 1, 2018 at 17:26 history answered fgrieu CC BY-SA 4.0