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Cryptography

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  • $\begingroup$ p256 has low order points? I thought cofactor was 1? $\endgroup$ Commented Jun 5, 2019 at 16:20
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    $\begingroup$ @WeCanBeFriends P-256 does not have low-order points (other than the point at infinity); our invalid curve does. $\endgroup$ Commented Jun 5, 2019 at 16:24
  • $\begingroup$ ahh alright, I saw your first sentence on using p256 as an example, so that confused me $\endgroup$ Commented Jun 5, 2019 at 17:36
  • $\begingroup$ Thanks! I was able to find low order point on a different curve using Sage by following this approach. $\endgroup$ Commented Jun 6, 2019 at 1:03