Skip to main content
13 events
when toggle format what by license comment
Nov 28, 2020 at 13:02 vote accept KMG
Nov 28, 2020 at 12:14 history edited fgrieu CC BY-SA 4.0
Polish
Nov 28, 2020 at 11:40 comment added fgrieu This is closely related to Why do we need Euler's totient function $φ(N)$ in RSA?. The bottom line is that it's wrong to assume $X^f\equiv X^{f\bmod m}\pmod m$, and in the question that's done when going from $e\cdot d \ \equiv \ 1\pmod{\phi(p\cdot q)}$ to the incorrect ${(X^e)}^d \equiv X \pmod{\phi(p\cdot q)}$.
Nov 28, 2020 at 11:28 history edited fgrieu CC BY-SA 4.0
Fix some of the notation
S Nov 28, 2020 at 11:20 history suggested Modal Nest CC BY-SA 4.0
clarity, as per comments. without understanding the maths it was difficult to understand the question.
Nov 28, 2020 at 10:11 comment added Modal Nest I've submitted an edit to your question which makes it clear I think (i left the maths alone!). The first answer suggests it wasn't clear to people who understood the maths too.
Nov 28, 2020 at 10:03 answer added ambiso timeline score: 3
Nov 28, 2020 at 10:00 review Suggested edits
S Nov 28, 2020 at 11:20
Nov 28, 2020 at 9:34 comment added KMG @ModalNest yes this is exactly what i mean which is it should decrypt correctly .
Nov 28, 2020 at 9:06 comment added Modal Nest I don't think your question is clear. Although it might just be my lack of mathematical ability. If you are simultaneously encrypting and decrypting, what is the purpose? Why would you do it? Do you mean it should work, but it doesn't, and you are asking mathematically why it doesn't?
Nov 28, 2020 at 8:50 comment added KMG @ModalNest I'm not putting them together I'm just demonstrating the process of encrypting then decryption at the same time.
Nov 28, 2020 at 8:48 comment added Modal Nest e is the public key and d is the private key. What is gained by putting them together? Assuming it works, isn't it just turning RSA into a resource-hungry symmetric cipher?
Nov 28, 2020 at 8:31 history asked KMG CC BY-SA 4.0