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    $\begingroup$ I suspect it might be possible, though I'm unsure. For instance, I believe Oleg Kiselyov showed that it's possible to implement the more 'dynamic' delimited operators (like shift0 and control(0)) in terms of shift, which seems implausible at first. Those let you break out of delimiters, so from there it seems like a matter of managing a token at each delimiter to determine whether you should continue shifting, which seems possible. If I find a conclusive reference, I'll link it. $\endgroup$ Commented May 7, 2019 at 1:36