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- $\begingroup$ Why is that so ? If the non-determinism is the problem does it imply that it won't work for NFA either ? $\endgroup$Robert777– Robert7772013-07-22 15:36:28 +00:00Commented Jul 22, 2013 at 15:36
- 3$\begingroup$ @Robert777: It won't work for NFA either, unless you determinize it first. For example, consider an automaton over unary alphabet, states A,B,C,D, transitions A -> B, B -> C, C -> C, A -> D, D -> D, initial state A, accepting states C,D. This automaton accepts all nonempty words. If you make C,D sinks the resulting language will be $\{a,aa\}$ instead of $\{a\}$. $\endgroup$sdcvvc– sdcvvc2013-07-22 15:43:25 +00:00Commented Jul 22, 2013 at 15:43
- 2$\begingroup$ The way I understand "sink" (all outgoing edges loop back) this won't work at all. $\endgroup$Raphael– Raphael2013-07-22 16:34:59 +00:00Commented Jul 22, 2013 at 16:34
- 1$\begingroup$ I assumed that as a mental shortcut by "sink" OP meant removing all outgoing edges (or pointing them to a sink in your sense). $\endgroup$sdcvvc– sdcvvc2013-07-22 17:13:18 +00:00Commented Jul 22, 2013 at 17:13
- $\begingroup$ @Raphael I really did mean removing all outgoing edges, sorry if I wasn't clear about it. $\endgroup$Robert777– Robert7772013-07-22 18:18:06 +00:00Commented Jul 22, 2013 at 18:18
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