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  • $\begingroup$ thanks again for the follow-up question. I do promise to come back to it as soon as I have time. Just for clarification: rows are subscripted with index $i$ and columns are referenced with index $j$, right? Additionally, I understand that the subindices of $T$ are given in the order $i, j$ (ie., row, column). Thus, I can see that in the second table, $T_{3,3}$ is wrong, but $T_{2,3}$ is correct ... (it seems from the sentence just below the second table that $T_{2,3}$ should be wrong) $\endgroup$ Commented Aug 25, 2015 at 1:31
  • $\begingroup$ Thanks @Carlos. The second table should look exactly like the second to last table (where $k=2$). Maybe I completely misunderstood your alternate formula but I thought we could calculate best-$p$ items of $n$-items without having to calculate a third index $k$. $\endgroup$ Commented Aug 25, 2015 at 5:18