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Signal Processing

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  • $\begingroup$ That explains why sinc function is merely an approximation. Thank you. I tried to replicate DTFT plot in above figure but to no avail. Can you provide me with the code? $\endgroup$ Commented Feb 28, 2017 at 8:38
  • $\begingroup$ @KlemenD: I've added the code. You just need to implement the given formula. $\endgroup$ Commented Feb 28, 2017 at 8:47
  • $\begingroup$ I was setting w = 2*pi * linspace(0,fs,500) and w0 = 2*pi*k/N*fs which gave me wrong result. I assume the DTFT formula expects w and w0 being relative frequencies? $\endgroup$ Commented Feb 28, 2017 at 9:33
  • $\begingroup$ @KlemenD: Yes, that's usually what is meant by writing $X(e^{j\omega})$. You also sometimes see $X(e^{j\omega T})$, where $T$ is the sampling interval. In that case, $\omega$ is not normalized. $\endgroup$ Commented Feb 28, 2017 at 9:38