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$\begingroup$ Thank you, this gives me new pointers to look at. I don't understand n your answer, how you calculate the cutoff as you say $ f_{cutoff} = \frac{f_{s}}{N} $, but you don't state what N, you have used with 44.1 kHz. $\endgroup$

boomkin
– boomkin

2020-08-10 12:40:08 +00:00
Commented Aug 10, 2020 at 12:40
1

$\begingroup$ Sorry, fixed. I was using N=32 as an example. $\endgroup$

Hilmar
– Hilmar

2020-08-10 14:06:11 +00:00
Commented Aug 10, 2020 at 14:06

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