Timeline for Frequency shifting with complex exponential
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 6, 2023 at 16:55 | vote | accept | PrematureCorn | ||
| Apr 5, 2023 at 21:21 | comment | added | Dan Boschen | @PrematureCorn If Hilmar answered your primary question, please select it to close this out. Review your other questions as well if still open and let the responders know what is missing still in your understanding. Thanks! | |
| Apr 5, 2023 at 2:44 | comment | added | Dan Boschen | @PrematureCorn this may help: $2\cos(2\pi 50e3 t) = e^{j2\pi 50e3 t}+e^{-j2\pi 50e3 t}$, which is how we see directly the positive 50KHz and negative 50KHz frequencies (which appear as two bins in the FFT). If you multiply that by $e^{j2\pi 15e3 t}$ you get $e^{j2\pi 65e3 t}+e^{-j2\pi 35e3 t}$. If you only wanted the 65KHz, you either need to high pass filter, or use the analytic signal as explained in the comments under your post. | |
| Apr 4, 2023 at 20:58 | comment | added | Hilmar | @PrematureCorn: "correct" in this context depends really on what exactly you want to do and why. There are some applications where complex signals are perfectly fine and others where they really don't make sense. | |
| Apr 4, 2023 at 19:29 | comment | added | PrematureCorn | Could you please add to your answer what the "correct" components are? Also, what would be the best practice of handling a real signal multiplied by a complex exponential? Should I filter it? | |
| Apr 4, 2023 at 19:07 | history | answered | Hilmar | CC BY-SA 4.0 |