Example 3:
Given the causal and stable impulse response
$$h(t)=e^{-t}u(t)$$
we know from the above that the corresponding transfer function
$$H(s)=\frac{1}{1+s}$$
must be analytic and decaying in the right half-plane, both of which is straightforward to verify. Furthermore, $H(s)$ must satisfy the Hilbert transform relations $(11)$ and $(12)$ on the imaginary axis. Splitting $H(j\omega)$ into real and imaginary parts gives
$$\mathscr{H}\left\{\frac{1}{1+\omega^2}\right\}=\frac{\omega}{1+\omega^2}$$
which is a well-known Hilbert transform pair (see this answer or this table).