Timeline for Is this 12 volt LED circuit correct?
Current License: CC BY-SA 3.0
15 events
| when toggle format | what | by | license | comment | |
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| Jan 21, 2015 at 14:29 | comment | added | WhatRoughBeast | @FraserDunn - 9) Another bad internet article. Using phosphor after-glow will, among other things, not provide any blue during the off-cycle. | |
| Jan 21, 2015 at 14:16 | comment | added | WhatRoughBeast | @FraserDunn - 4) Fan does no such thing. Power draw by the fan will be a few watts. It will not be coupled to the heatsink, so it won't heat the LEDs. And it will greatly increase the cooling ability of the heatsink. So, no. No increased heating of the LEDs and no irony. | |
| Jan 21, 2015 at 14:14 | comment | added | WhatRoughBeast | @FraserDunn - 3) Excellent idea. Now you have to learn about heat sinks, how to specify them and how to use them. Good luck. | |
| Jan 21, 2015 at 14:13 | comment | added | WhatRoughBeast | @FraserDunn - 1) It's a bad circuit from the internet. If you don't know not to trust everything you find on the internet, now's the time to learn. And no, the compensation makes things better, not worse. And it doesn't do it electromechanically. | |
| Jan 21, 2015 at 8:29 | comment | added | Fraser Dunn | 9)” Absolutely. Of course, each bank of LEDs will only be on for half the time, so the total light will remain the same, so you might want to rethink this one. “ >>> The idea from the article is that the LED will remain shining for a brief while after the power is switched temporarily off and before this can totally fade the power is restored. Thus you DOUBLE your light power with half the circuit energy. But will the plant notice this? | |
| Jan 21, 2015 at 8:25 | comment | added | Fraser Dunn | 8. Yes I need some kind of small load loop to use a variable resistor. I have another schematic. But I would have to merge this with this one. Which I am willing to do! An article I have confused me because it said get a “470 ohm potentiometer( rheostat)” but a potentiometer is not the same as a rheostat. More to learn. I thought they were the same because of an article. The article does state you need this loop because 470 ohm can only control little wattage. I hope the article is right. Must studying it first! Use the brains first! Don’t follow blindly what is said or written! | |
| Jan 21, 2015 at 8:06 | comment | added | Fraser Dunn | 7. I'm re-learning my resistor colours. | |
| Jan 21, 2015 at 8:03 | comment | added | Fraser Dunn | 6. Yes NO load with heat discard power supply to recycle bin. | |
| Jan 21, 2015 at 7:59 | comment | added | Fraser Dunn | 5. Good point the error could be input or output. A good Main Fuse box looks after the input error. For the output error have some item that I know the actual load – check. Get a super resistor. I’ll have to research the idea of a 6 ohm resistor that can withstand 25 watts minimum. Have to get a book and learn or re-learn this matter and other matters. Thank You. | |
| Jan 21, 2015 at 7:52 | comment | added | Fraser Dunn | 4. Exceeded temperature for the parts – check. Must mount good to keep components cool– check. Fan creates an ironic problem since adding one makes the load of the circuit greater and in turn generates more heat caused by the fan – check! THAT IS VITAL! Cost Metrics again, does a person design for intensity and low life LED or medium intensity and medium LED life or low intensity and long lasting LED life? This is gardening so looks like somewhere above medium. | |
| Jan 21, 2015 at 7:44 | comment | added | Fraser Dunn | 3. I wanted to build a stand alone cool temperature project without using a fan. | |
| Jan 21, 2015 at 7:38 | comment | added | Fraser Dunn | 2. Yes this is cost metric and as you say a voltage regulator is some item I wish to add to keep the "proper" intensity and colour for growing those tomatoes at home. | |
| Jan 21, 2015 at 7:35 | comment | added | Fraser Dunn | 1. The numbers are not mine but rather a schematic from the Internet. I believe they are typicals yes. “To some degree the LEDs will compensate by requiring a greater voltage drop for this current, which will reduce the current level…” So the compensation makes this even worse you are saying? Interesting! This is so important to know! I learned something vital! I Wonder how the LEDs compensate to make matters worse? How they electromechanically do that!? | |
| Jan 19, 2015 at 9:27 | history | edited | WhatRoughBeast | CC BY-SA 3.0 | added 353 characters in body |
| Jan 19, 2015 at 9:11 | history | answered | WhatRoughBeast | CC BY-SA 3.0 |